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View Full Version : Problem in php ajax post value.



youlichika
06 Dec 2010, 07:40 PM
I want to post value from index.php, then get the value by self without refresh the page. one botton with two values, I want explode them and finally get $namea and $nameb. then use them in other php part.
but when I use echo $name, in the source code, I can see <div id='msg'></div>(html tag), this is not a pure value, so I tried to use strip_tags, but the value lost. it seems the left the ajax pointed div tag, the value also gone.

index.php


<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<script language="javascript">
function saveUserInfo() {
var msg = document.getElementById("msg");
var f = document.user_info;
var userName = f.user_name.value;
var url = "value.php";
var postStr = "user_name="+ userName;
var ajax = false;

if(window.XMLHttpRequest) {
ajax = new XMLHttpRequest();
if (ajax.overrideMimeType) {
ajax.overrideMimeType("text/xml");
}
} else if (window.ActiveXObject) {
try {
ajax = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try {
ajax = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e) {
}
}
}

if (!ajax) {
window.alert("wrong");
return false;
}

ajax.open("POST", url, true);
ajax.setRequestHeader("Content-Type","application/x-www-form-urlencoded");
ajax.send(postStr);
ajax.onreadystatechange = function() {
if (ajax.readyState == 4 && ajax.status == 200) {
var myPhpVariable = ajax.responseText;
msg.innerHTML = myPhpVariable;
// myPhpVariable is now a variable which you can use
alert( myPhpVariable );
}
}
}
</script>
</head>
<body>
<?php
echo $name="<div id='msg'></div>";
$name1=strip_tags($name);
$name2 = explode("|",$name1);
$namea=$name2[0];
$nameb=$name2[1];
?>
<form name="user_info" id="user_info" method="post">
<input name="user_name" type="hidden" value="abc|def" /><br />
<input type="button" value="abc|def" onClick="saveUserInfo()">
</form>
</body>

value.php


<?php
echo $_POST["user_name"];
?>