I'm using the following AHAH code in my site:

PHP Code:
        function ahah(urltarget) {
          
document.getElementById(target).innerHTML ' Fetching data...';
          if (
window.XMLHttpRequest) {
            
req = new XMLHttpRequest();
          } else if (
window.ActiveXObject) {
            
req = new ActiveXObject("Microsoft.XMLHTTP");
          }
          if (
req != undefined) {
            
req.onreadystatechange = function() {ahahDone(urltarget);};
            
req.open("GET"urltrue);
            
req.send("");
          }
        }  
        
        function 
ahahDone(urltarget) {
          if (
req.readyState == 4) { // only if req is "loaded"
            
if (req.status == 200) { // only if "OK"
              
document.getElementById(target).innerHTML req.responseText;
            } else {
              
document.getElementById(target).innerHTML=" AHAH Error:\n"req.status "\n" +req.statusText;
            }
          }
        }
        
        function 
load(namediv) {
            
ahah(name,div);
            return 
false;
        } 
with the following link:
PHP Code:
<a onclick="load('production.php','textArea');return false;" href="consulting.php">Overview</a
Which works great. My question is, how do I modify the script/link reference to make it load TWO pages into TWO divs on the same page? The following types of link references do not work:

PHP Code:
<a onclick="load('production.php','textArea','none.php','pulledContent');return false;" href="production.php">Overview</a></li
PHP Code:
<a onclick="load('production.php','textArea','none.php','pulledContent');return false;" href="production.php">Overview</a
PHP Code:
<a onclick="load('production.php','textArea');load('none.php','pulledContent');return false;" href="production.php">Overview</a